Question

in fig. AB and CD are two equal chords of a circle with centre O. OP and OQ are perpendiculars on chords AB and CD respectively. if angle POQ=105°, then angle APQ is equal to what?


Solve.​

Answer 1

Answer:

∠APQ=75°

Step-by-step explanation:

Given, AB=CD,

OP=OQ (Equal chords are equidistance from the centre)

⇒∠OQP=∠OPQ

150°+∠OQP+∠OPQ=180°

⇒∠OPQ=15°

Given, ∠OPA=90°

Hence, ∠APQ=90-15=75°