Question

in fig. AB, CD and EF are three concurrent lines, meeting at O. fimd the value of a. NO SPAM PLS! ​

Answer 1

Answer:

a= 90-4d

Step-by-step explanation:

If we take centre as O

FOB =2a (Vert. Opp. Angles)

5d + 2a + 3d = 180° (Straight Anglez)

2a = 180° - 8d

a = 180-8d

2

a = 90° - 4d

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Answer 2

let common point be O

angle COF = angle EOD (vertically opposite angle)

now

angle AOB = 180

2a + 5a + 3a = 180

9a = 180

a = 20