In Fig.AB || CD, PQ||AX and angle BAC = 70°, find
angle DPQ
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Answered by
5
Answer:
70°+ angle ACP =180°
angle ACP =110°
now
angle ACP = angle DPQ
THEREFORE ANSWER IS 110°
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Answered by
4
Answer:
Extend the line PQ on the line AB.Now,ACPQ becomes a parallelogram and in a parallelogram, opposite angles are equal.
So angle QPC will be 70°and angle DPQ will be 180°-70°=110°
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