Question

in fig ab||dc. if x=4/3y and y=3/8z, find the values of x,y,z,​

Answer 1

Answer:

I have not understand please some one give the answer

Answer 2

Answer:

pls. mark me brainleist

Step-by-step explanation:

AB∥DC; x=

3

4

​

y and y=

8

3

​

z

AB∥DC,

⇒  ∠ABD=∠BDC               [ Alternate angles ]

∴  ∠ABD=∠BDC=x  

In △BDC,

x+y+z=180

o

⇒  

3

4

​

y+

8

3

​

z+z=180

o

First we will solve the  

3

4

​

y.

Since, y=

8

3

​

z

∴  

3

4

​

×

8

3

​

z

⇒  

24

12

​

z

⇒  

2

1

​

z

Now,  

2

1

​

z+

8

3

​

z+z=180

o

⇒  

8

4z+3z+8z

​

=180

o

.

⇒  

8

15z

​

=180

o

.

⇒  15z=180

o

×8

⇒  z=

15

1440

​

⇒  z=96

o

.

Now, y=

8

3

​

z

⇒  y=

8

3×96

o

​

⇒  y=

8

288

​

⇒  y=36

o

.

Now, x=

3

4

​

y

⇒  x=

3

4×36

o

​

⇒  x=

3

144

​

⇒  x=48

o

.

∴  x=48

o

,y=36

o

 and z=96

o

.