Question

In Fig, AB II CD and they cut PQ at E, F and
QR at G, H respectively. If angle AEP = 70° and angle CHQ=
140°, find angle PQR.
​

Answer 1

Answer:

30°

Step-by-step explanation:

Angle bep = Angle bef ......( vertically opposite angles )

Angle bef = 70 °

Angle bef = angle dfq

angle dfq = 70°

angle hfq +angle dfq = 180 ...... ( linear pair )

70 + hfq = 180

angle hfq= 110°

angle chq +angle fhq = 180° ..... ( linear pair )

140 +fhq =180

fhq = 40°

in triangle fhq

angle hfq +Angele fhq + angle fqh = 180 .....( angle sum property)

110 + 40 + fqh = 180

150 + fqh =180

angle fqh = 30°

angle fhq = angle pqr