Question

in fig. AB is a diameter of the circle. DC is a parallel to AB and angle CAB=25 did angle ADC​

Answer 1

Answer:

Step-by-step explanation:

•according to the question

the following picture is given below

∠CAB=25°(according to the question)

∠ACB=90°

we know,

∠CAB+∠ACB+∠ABC=180°(Angle Sum Property)

25°+90°+∠ABC=180°

or,115°+∠ABC=180

so,∠ABC=65°

∠ABC+∠ADC=180°

as we know that the Sum of opposite angles of cyclic quadrilateral is 180°

65°+∠ADC=180°

so,

∠ADC=115°

so the final answer is angle ADC is 115°

Hope it helps..

Answer 2

Answer:

Step-by-step explanation:

Where is your fig.