Question

in fig ab parallel cd angle abr = 45 angle rod = 105 find angle odc​

Answer 1

Answer:

30 degree

Step-by-step explanation:

Let us draw the lines OQ and RP as shown in the above figure.

So, ∠ABO = ∠BPO = 450

In Δ OPD,

∠OPD + ∠POD + ∠ODP = 180 degree

=> 450 + 105 + ∠ODP = 180 degree

=> 150 + ∠ODP = 180 degree

=> ∠ODP = 180 - 150. degree

=> ∠ODP = 30 degree

Hence, ∠ODP = 30 degree

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Answer 2

Answer:

answer is 30 degree

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