In fig AB||XY, angle
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angle YXB=angle ABX(since AB is parallel to XY alternate angles are equal)
so angle ABX=35°
angle ACB=180-(53°+35°)=92°
so angle ABX=35°
angle ACB=180-(53°+35°)=92°
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hey...
As AB||XY ,
angle YXC = angle ACB = 35°
sum of angles in a triangle = 180°
53° + 35° + x° = 180°
88° + x° = 180°
x° = 180 - 88°
x° = 92°
As AB||XY ,
angle YXC = angle ACB = 35°
sum of angles in a triangle = 180°
53° + 35° + x° = 180°
88° + x° = 180°
x° = 180 - 88°
x° = 92°
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