In Fig.ABC and ABD are two triangles on the same base AB.If line segment CD is bisected by AB at O,Show that ar(ABC)=ar(ABD).
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Answered by
8
1.CO=OD (Given)
2. Area of triangle ABC= 1/2xbasexheight
=1/2x AB x CO
3. Area Of triangle ABD= 1/2 x base x height
= 1/2 x AB x OD
From 1 & 3, we know that,
CO= OD
therefore
4.Area of triangle ABD = 1/2 x AB xCO
Therefore,from 2 & 4,
Ar(ABC)= Ar(ABD
2. Area of triangle ABC= 1/2xbasexheight
=1/2x AB x CO
3. Area Of triangle ABD= 1/2 x base x height
= 1/2 x AB x OD
From 1 & 3, we know that,
CO= OD
therefore
4.Area of triangle ABD = 1/2 x AB xCO
Therefore,from 2 & 4,
Ar(ABC)= Ar(ABD
Answered by
11
In ∆ ABC & ∆ ABD, WE GET :-
AB is common side
CB=AD (since all sides of rhombus are equal)
AC=BD (since all sides of rhombus are equal
So, ∆ABC is congruent to ∆ABD (by S-S-S rule of congruency)
Hence, their area will also be equal.
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