Question

In fig. ABCD is a cyclic quadrilateral.if angle BAC=50 and angle DBC=60,then find angle BCD

Answer 1

Given :- angle BAC = 50° and angle DBC = 60°
To find :- angle BCD.
Solution :-

angle BAC = angle CDB [Angles on the same segment of a circle are equal]

angle CDB = 50°

In triangle BCD,

angle BCD + angle CDB + angle DBC = 180° [Angle sum property of a triangle]

angle BCD + 50° + 60° = 180°
angle BCD + 110° = 180°
angle BCD = 180° - 110°
angle BCD = 70° ANSWER


HOPE IT HELPS YOU....

Answer 2

Answer:

hey mate here is ur answer in the pic....

hope it helps you