Question

In fig., ABCD is a cyclic quadrilatreral. If <BAC = 50° and <DBC = 60°, then find <BCD. D C 60 ° 500 A B TT​

Answer 1

Answer:

Step-by-step explanation:

Here ∠BDC=∠BAC=50

∘

since angles in same segment are equal

In △BCD, we have

∠BCD=180

∘

−(∠BDC+∠DBC)

=180

∘

−(50

∘

+60

∘

)

=180

∘

−110

∘

=70

∘

∴∠BCD=70

∘

Answer 2

Here ∠BDC=∠BAC=50°

( angles in same segment are equal )

In ΔBCD we have,

∠BCD=180°−(∠BDC+∠DBC)

=180° −(50° +60° )=70°