Question

In fig.,ABCD is a parallelogram,AE parallel to DC and CF parallel to AD,if AB =16 cm,AE =8cm and CF = 10 cm,find AD​

Answer 1

Step-by-step explanation:

in parallelogram opposite sides are equal

AB= DC , AD= BC

DC=16cm

area of parallelogram= base× height

base=DC

height=AE

Area of parallelogram = 8×16= 128cm^2

area of parallelogram with height CF and base AD = base × height

128cm^2 = 10cm × AD

AD=12.8cm

HOPE YOU WILL GET YOUR ANSWER

Answer 2

Question :-

In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.

Answer :-

We have, AE ⊥ DC and AB = 16 cm

∵ AB = CD [Opposite sides of parallelogram]

∴ CD = 16 cm

Now, area of parallelogram ABCD = CD x AE

= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]

Since, CF ⊥ AD

∴ Area of parallelogram ABCD = AD x CF

⇒ AD x CF = 128 cm

⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]

⇒ AD = 128/10 cm = 12.8 cm 10

Thus, the required length of AD is 12.8 cm

Hope it helps ❤ Mrk as brainliest