Question

In fig. ABCD is a rectangle. Find the value of x and y

Answer 1

Area of rectangle=l*b
Area of rectangle = 30*14
= 420 Cm square
In the formula of area of rectangle,take (x-y) as breadth and 30 cm as length
Area of rectangle = l*b
420= 30*(x-y)
420/30=x-y
14=x-y -1)
Now again in the formula of area of rectangle ,take length as (x+y) and breadth as 14 cm
Area of rectangle =l*b
420=14*(x+y)
420/14=x+y
30=x+y -2)
Solve equation 1) and 2)
x-y=14
x+y=30
- - -
_______
-2y= -16
y= -16/-2
y=8
Substitute y=8 in equation 1)
x-y=14
x-8=14
x=14+8
x=22

Answer 2

Answer:

Step-by-step explanation:

let AB and CD lengths be x,

BC and DA are breadths y.

Area of rectangle is LB so,

AB =CD

BC =DA

So area is xy