In fig. ABCD is a rhombus Angle DCE=80 degree.Find angle X, Y, Z
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dce=bde(interior alternate angles)
80=y
x=y(interior alternate angles)
therefore x=80
y=x+z (exterior angle property)
80=80+z
z=80-80=0
80=y
x=y(interior alternate angles)
therefore x=80
y=x+z (exterior angle property)
80=80+z
z=80-80=0
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hope this is correct
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angle bcd will be 100 degree by using linear pair and z will be equal to angle bcd
then x will be equal to y and both the triangle that is a b D and BCG will be congruent so
first by using the angle sum property of quadrilateral will find angle abc and ADC so they were becoming so angle abc and angle ADC will be 80 degrees
angle a BD will be equal to DBC because both the triangle are congruent and we know that the diagonals bisect the angles and divides a rhombus into two equal halves or two congruent half
or two isoceles triangle
so angle abd will be half the angle abc which will be 40 degree and similarly y will also be 40 degree
I hope this might help you
then x will be equal to y and both the triangle that is a b D and BCG will be congruent so
first by using the angle sum property of quadrilateral will find angle abc and ADC so they were becoming so angle abc and angle ADC will be 80 degrees
angle a BD will be equal to DBC because both the triangle are congruent and we know that the diagonals bisect the angles and divides a rhombus into two equal halves or two congruent half
or two isoceles triangle
so angle abd will be half the angle abc which will be 40 degree and similarly y will also be 40 degree
I hope this might help you
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