Question

in fig , abcd is a square of side14 cm & apd & bcp are semicircle .find area & perimeter of shaded region

Answer 1

A. of shaded region = A. of sq. ABCD-2×A.OF SEMICIRCLE

$14 {}^{2} -2 \times ( \frac{1}{2} \times \frac{22}{7} \times 7^{2})$
$196 - 154$
42 cm^2

p. of shaded region = AB+DC+2×(CIRCUMFERENCE OF SEMI CIRCLE)
14+14+2(22/7×7)
28+2×(22)
28+44
72CM