In fig ABCD is a triangle. find value of x and y
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Answered by
48
x-y =14.....(i)
x+y=30.......(ii)
so, x=14+y....(iii)
in equ ii,
14+y+y=30
14+2y=30
2y=16
y=8
so x =14+y
=14+8
=22
x+y=30.......(ii)
so, x=14+y....(iii)
in equ ii,
14+y+y=30
14+2y=30
2y=16
y=8
so x =14+y
=14+8
=22
Answered by
20
In the given figure ABCD is a rectangle.
∴ AB = CD
& BC = AD
(∵ Opp. sides of a rectangle are equal)
∴ 30 = x +y..........1st
& 14 = x - y.........2nd
Now, by solving both the questions by elimination method
x + y = 30
x - y = 14
__________
2x = 44
∴ x = 22 cm
Now, substituting x = 22 in equation 1
x + y = 30
22+ y = 30
∴ y = 8 cm
∴ x = 22 cm and y = 8 cm
Hope this helps you !
# Dhruvsh
∴ AB = CD
& BC = AD
(∵ Opp. sides of a rectangle are equal)
∴ 30 = x +y..........1st
& 14 = x - y.........2nd
Now, by solving both the questions by elimination method
x + y = 30
x - y = 14
__________
2x = 44
∴ x = 22 cm
Now, substituting x = 22 in equation 1
x + y = 30
22+ y = 30
∴ y = 8 cm
∴ x = 22 cm and y = 8 cm
Hope this helps you !
# Dhruvsh
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