In fig. ∆ABE is congruent to ∆ACD. Prove that ∆ADE~∆ABC.
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AD=1/2×AB
SIMILARLY AE=1/2×AC
TGEREFORE AD=AE=DE
AB=BC=AC
SIMILARLY AE=1/2×AC
TGEREFORE AD=AE=DE
AB=BC=AC
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here is your answer mate
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But ∆ABE is CONGRUENT to ∆ACD not similar
same
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