In Fig. AC =AE , AB=AD and angle BAD =angle EAC . Show that BC=DE. [Answer in detail ]
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Answer:
It is given that ∠BAD=∠EAC
∠BAD+∠DAC=∠EAC+∠DAC [add ∠DAC on both sides]
∴∠BAC=∠DAE
In △BAC and △DAE
AB=AD (Given)
∠BAC=∠DAE (Proved above)
AC=AE (Given)
∴△BAC≅△DAE (By SAS congruence rule)
∴BC=DE (By CPCT)
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