In fig, ad⊥bc , ab=25 ad=17cm find bd,dc,bc
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Given :
- In ΔABC :
- ∠ADC = ∠ABC = 90°
- AD ⊥ BC
- AB = 25cm
- AD = 17cm
- AD = 15cm
To find
- Length of :
- BD
- DC
- BC
Solution :
- In ΔADB :
- ∠ADB = 90°
- BD² = AB² - AD² (Pythagoras Theorem)
- BD² = 25² - 15²
- BD² = 625 - 225
- BD² = 400
- BD = √400
- BD = 20
☯ Length of BD = 20cm
- In ΔADC :
- ∠ADC = 90°
- DC² = AC² - AD² (Pythagoras Theorem)
- DC² = 17² - 15²
- DC² = 289 - 225
- DC² = 64
- DC = √64
- DC = 8
☯ Length of DC = 8cm
- BC = BD + DC
- As BD and DC together make up BC
- BC = 20 + 8
- BC = 28
☯ Length of BC = 28cm
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