Question

In fig angle AB||CD, AF||ED, angle AFC= 68º and angleFED = 42 find angle EFD


pls help​

Answer 1

Answer:

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

Angle AFC+EFD+AFE=180

68+42+x=180

110+x=180

X=180-110=70

Therefore AEF =70

Answer 2

Answer:

Step-by-step explanation:

Given: AB || CD

AF || ED

∠AFC = 68°

∠FED = 42°

To find: ∠EFD

Solution: Since AB || CD and AF is the transversal, then ∠AFC = ∠EDF = 68°(corresponding angles)

In ΔEFD, ∠FED = 42°, ∠EDF = 68°

therefore, applying the angle sum property of a triangle

∠FED + ∠EFD + ∠EDF = 180°

42° +  ∠EFD + 68° = 180°

∠EFD + 110° = 180°

∠EFD = 180° - 110°

∠EFD = 70°

Hence ∠EFD = 70°