In fig,Angle ABC 25° ,find angle ACO=
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Given : ∠ABC = 25°
To Find : ∠AOC
Solution:
AB & CB are tangents
Hence ∠OAB = LOCB = 90°
∠ABC = 25°
∠AOC = ?
Sum of angles of quadrilateral AOCB = 360°
=> ∠AOC + 2OCB + ∠ABC + ∠OAB =
360°
=> ∠AOC + 90° + 25° + 90° = 360°
=> ∠AOC = 155°
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Answer:
ACO=165°
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