Question

In fig,angle ABC =70°,angle ACB =32° ,find angle BDC​

Answer 1

its the correct answer..

Answer 2

Given:

Angle ABC=70°

Angle ACB=32°

To find:

The angle BDC

Solution:

The angle BDC is equal to 78°.

We can find the angle by following the given steps-

We know that the sum of all angles in a triangle is 180°.

So, in ΔABC, angle ABC+angle ACB+ angle BAC=180°

We are given that the angle ABC=70° and angle ACB=32°.

On putting the values, we get

70°+32°+angle BAC=180°

102°+angle BAC=180°

Angle BAC=180°-102°

Angle BAC=78°

Now, we know that the angles in the same segment are equal in a circle.

This means that the angle BAC=angle BDC.

So, angle BDC=78°.

Therefore, the angle BDC is equal to 78°.