Question

in fig angle B greater angleA and angleC greater angleD.show that AD greaterBC.​

Answer 1

Answer:

$\sf{ \therefore{AD}} < BC$

Step-by-step explanation:

$\sf{In \triangle{AOB}}$

$\sf{ \angle{B} = \angle{A}$

$\sf{\therefore{AO< BO}} - - - 1$

$\sf{In\triangle{COD}}$

$\sf{ \angle{C}}= \angle{D}$

$\sf{ \therefore{OD < OC}} - - - 2$

$\sf{Adding \: 1 \: and \: 2}$

$\sf{(AO + OD) < BO + OC)}$

$\sf{ \therefore{AD < BC}}$

$\bf \pink{ \underline{Please \: mark \: it \: as \: brainlist \: answer}}$