Question

in fig angle bac = 30. Show that chord bc is equal to the radius of the circle.
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Answer 1

angle BOC = 2*angle BaC

( angle suspended by the radius is double )

so angle BAC= 60

IN TRIANGLE BOC ,

OB=OC(RADIUS)

SO BY ANGLE SUM PROPERTY OF TRIANGLE .

U CAN FIND THAT ANGLE B = ANGLE C= 60 .

SO triangle is equilateral .

so BC is equal to radius of circle ..

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