Question

in fig angle BCD =angle ADC and angle ACD= angle BDA . prove that AD=BC and angle A =B​

Answer 1

Answer:

in ∆ADC and ∆BCD

ANGLE BCD= ADC(GIVEN)

ANGLE ACD=BDA (GIVEN)

CD=CD (COMMON)

::∆ADC CONGRUENT TO ∆BCD

(ASA)

AD=BC (CPCT)

<B=<A (CPCT)

HENCE PROVED ,,,,,,,