In fig angle BCD is an exterior angle of angle ABC. If angle BCD=3x, angle A=x and angle B=80 degree. Find the value of x
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the exterior angle is the sum of the opposite two angles of the triangle
3x = 80 + x
2x= 80
x=40
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answer=40
=x+ 40=3x
=x-3x= -80
=2x=-80
=x=80÷2
=x=40
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