in fig ∆AOC = x+35° and ∆BOC = x-15° then ∆BOC=_________ (a) 115° (b) 80° (c) 65° (d) 55°
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Step-by-step explanation:
In the given figure,
The two angles AOC and BOC form a linear pair.
So, their sum is 180°.
(x+35)+(x-15)=180°
x+35+x-15=180°
2x+20=180°
2x=180-20
2x=160
x=160/2
x=80°
Now find the value of BOC
BOC= x-15
=80-15
=65°
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