In fig. APB and APQ are semi circles and AO=OB. If the perimeter of the figure is 40 cm find the area of the shaded region. (use pie=22/7)
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angle=90
area of circle=22/7×r^2
circumferece=2r+l=40
2r+22/7×r×90/180=40
hence,25r+11r=280
r=56/5
area of circle=394.24
area of minor sector=22/7×56/5×90/360
=98.56
area of shaded region =394.24-98.56
=295.68
area of circle=22/7×r^2
circumferece=2r+l=40
2r+22/7×r×90/180=40
hence,25r+11r=280
r=56/5
area of circle=394.24
area of minor sector=22/7×56/5×90/360
=98.56
area of shaded region =394.24-98.56
=295.68
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