Question

in fig.APB and AQP are semicircles and AO=OB.If the perimeter of the figure is 40 cm,find the area of the shaded region.(Use pie =22/7)
plzz help its urgent nd with proper explanation.

Answer 1

the perimeter of the given figure is 3/4×2πr +2r
solve for r .
use r to find area which is 3/4×πr2

Answer 2

Answer:

$\text{Area of shaded region is }169.76 cm^2$

Step-by-step explanation:

Given in figure APB and AQP are semicircles and AO=OB.

Perimeter of figure is 40 cm.

We have to find the area of shaded region.

$\text{Perimeter of figure=}(2\pi r)\times \frac{3}{4}=40$

⇒ $r=\frac{80}{3\pi}$

$\text{Area of shaded region }=\pi r^2\times \frac{3}{4}$

$A=\pi\times (\frac{80}{3\pi})^2 \times \frac{3}{4}$

$=\frac{1600}{3\pi}=169.765272631\sim169.76 cm^2$

$\text{Area of shaded region is }169.76 cm^2$