Question

in fig. BC parallel DE , angle APC =150, anglePAQ =30.find the value of x

Answer 1

hi here is your answere

Answer 2

angle APQ=180-150=30°

Sum of angles in triangle =180

30+30+angle AQP=180

angle AQP=180-60=120


As BC||DE

THEN,
x=120 =angleAQP(Corresponding angle)