Math, asked by babitachauhan70935, 23 days ago

In fig., BE is parallel to CD,BA=BC,angle ABE=20° and angle DCG=60°. Determine angle FAC

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Answered by pallavichondhalkar
6

Answer:

so as BE IIDC

ebc=dcg

so abc 60°-20° = 40°

as a+b+c= 180°

a+a+40=180°

SO.

a= 140/2=70°= bac

as baf = 180° (linear pair)

bac+fac = 180°

70°+fac=180°

fac=180°-70°-110°

Step-by-step explanation:

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