In fig., BE is parallel to CD,BA=BC,angle ABE=20° and angle DCG=60°. Determine angle FAC
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Answer:
so as BE IIDC
ebc=dcg
so abc 60°-20° = 40°
as a+b+c= 180°
a+a+40=180°
SO.
a= 140/2=70°= bac
as baf = 180° (linear pair)
bac+fac = 180°
70°+fac=180°
fac=180°-70°-110°
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