Question

In fig below AB = z, AC = 4√3, BC = 8, PQ = 3, PR = y and QR = 6. Also triangleABC ~ trianglePQR, then find

the value of y + z.​

Answer 1

△PQR is a right angle triangle then

(QR)

2

=(PR)

2

+(PO)

2

(6)

2

=(y)

2

+(3)

2

y=

36−9

y=

27

y=

9×3

y=3

3

△ABC is a right angle triangle then

(BC)

2

=(AB)

2

+(AC)

2

(8)

2

=(z)

2

+(4

3

)

2

z=

64−48

z=

16

z=4

∴y+z=4+3

3

Or

This can be done using SSS criteria as both triangles are given to be similar.