Question

in fig. chord EF || chord GH. prove that chord EG = chord FH.​

Answer 1

Step by step explanation ⤵️⤵️

EFG=∠FGH .. property of alternate angles of parallel lines

(I) ∠EFG=

2

1

m(arcEG) inscribed angle theorem (II)

∠FGH=

2

1

m(areFH)inscribed angle theorem (III)

∴m(arcEG)=m(arcFH)from (I), (II), (Ill)

chord EG= chord FHChords corresponding to congruent arcs of a circle are congruent.