Question

in fig circle with centre D touches the sides of ang ACB at A and B . If ang ACB = 52° find m ang ADB=?​

Answer 1

Answer:

LADB=128 degree

ADBC is a cyclic Quadrilateral

opposite angles are supplementary

so I80-52=128 degree is answer

Answer 2

Answer:

$given \: \: \\ \\ abcd \: is \: a \: cyclic \: quadrilaterl \\ opposite \: angle \: are \: supplementary \\ so \\ 180 - 52 \\ = 128$

THESE IS YOUR ANSWER..........FRIEND

MARK AS BRAINLIEST ❤