Question

in fig DE||AC and DF||AE prove that BF/FE= BE/EC​

Answer 1

Answer:

make me brainliest

Step-by-step explanation:

GIVEN:

In ∆BAC, DE || AC

BE/EC = BD/DA………..(1)

[ By Thales theorem(BPT)]

In ∆BAE, DF || AE  (GIVEN)

BF/FE = BD/DA………..(2)

[ By Thales theorem(BPT)]

(From eq 1 and 2)

BF/FE = BE/EC

FE/BF = EC/BE    [reciprocal the terms]

Hence proved.

HOPE THIS WILL HELP YOU..

Answer 2

Answer:

Can you send me a figure. Bcz , answer is dependent on what type of figure is that