In fig. DE||AC and DF||AE. Prove that BF/FE = BE/EC.
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Basic Proportionality Theorem: If a line is parallel to a side of a triangle which intersects the other sides into two distinct points, then the line divides those sides in proportion.In triangle ABC, DE is parallel to AC
Therefore,
By Basic proportionality theorem
......(1)
In triangle BAE, DF is parallel to AE
Therefore,By Basic proportionality theorem
...... (2)
From (1) and (2), we get
Hence, Proved.
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