Question

In fig. DE//BC,FIND 'X'.

Answer 1

brother , please show where is your diagram?

Answer 2

Answer:

Step-by-step explanation:Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.

To find: x

In △ABC, we have  

DE || BC

Therefore [By Thale's theorem]

AD/DB = AE/EC

AD × EC × = AE × DB

x(x-1) = (x-2)(x+2)

x2 - x = x2 - 4

x = 4

hope it helps