In fig. DE//BC,FIND 'X'.
sahildalal1986:
Where is the figure
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Answered by
15
brother , please show where is your diagram?
Answered by
10
Answer:
Step-by-step explanation:Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.
To find: x
In △ABC, we have
DE || BC
Therefore [By Thale's theorem]
AD/DB = AE/EC
AD × EC × = AE × DB
x(x-1) = (x-2)(x+2)
x2 - x = x2 - 4
x = 4
hope it helps
What if AD=X, DB=X-1,AE=X+3,EC=X+5
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