Question

in fig. find the perimeter of triangle ABC if AP=10 cm .

Answer 1

From the given diagram we can see that AP = 10cm

If AP = 10 the AQ = 10 Because AQ and AB are the tangent to the circle from a common point A

Similarly, PB = BM and CM =CQ

Also, AP =AB + PB and AQ = AC + CQ

To find the Perimeter of triangle ABC

Perimeter of ABC = AB + BM + CM + AC

                    = AB + PB + CQ + AC  (since PB = BM and CM =CQ)

                    = (AB + PB) + (CQ + AC)

                    = AP + AQ =10 +10 =20cm

Therefore Perimeter of triangle ABC =20 cm

Answer 2

Answer:

20cm

Step-by-step explanation:

AP=BP (two tangent in a circles are equal)

PB=BM (two...................................)

CM=CQ ( two...)

ABC= AB+BM+CM+AC

=AB+PB+CQ+AC

= (AB+PB) + (CQ+AC)

=AP+AQ

= 10+10

=20CM