Question

In fig. given Line AB and CD intersect at O. If ∠AOC + ∠BOE =70˚ and ∠BOD =40˚, Find ∠COE . ​

Answer 1

Step-by-step explanation:

Given:∠BOD=40∘

Since AB and CD intersects, ∠AOC=∠BOD(vertically opposite angles)

∠AOC=40∘

Also,∠AOC+∠BOE=70∘

⇒∠BOE=70∘−∠AOC=70∘−40∘=30∘

We need to find reflex∠COE

Reflex∠COE=360∘−∠COE

Now, ∠AOC+∠COE+∠BOE=180∘

⇒∠COE+(∠AOC+∠BOE)=180∘

⇒∠COE+(40∘+30∘)=180∘

⇒∠COE=180∘−70∘=110∘

Reflex∠COE=360∘−110∘=250∘

Answer 2

Answer:

Step-by-step explanation:

Given:∠BOD=40  

 

Since AB and CD intersects, ∠AOC=∠BOD(vertically opposite angles)

∠AOC=40  

 

Also,∠AOC+∠BOE=70  

∠BOE=70−∠AOC=70−40=30

⇒∠BOE=70   −∠AOC=70=30

Reflex ∠COE=360-∠COE

∠AOC+∠COE+∠BOE=180  

⇒∠COE+(∠AOC+∠BOE)=180

⇒∠COE+(40+30=180  

∠COE=180−70  =110

Reflex∠COE=360−110=250