in fig ,if 30 then y
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Answer:
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Step-by-step explanation:
Find value of k.
2x
2
+kx−5=0 & x
2
−3x−4=0
→x
2
−3x−4=0
x
2
−4x+x−4=0
x(x−4)+1(x−4)=0
(x+1)(x−4)=0
x=−1 and x=4
→ one root is common
∴2(−1)
2
+k(−1)−5=0
∴2−k−5=0
∴k=−3
Or
2(4)
2
+k(4)−5=0
∴32+4k−5=0
∴k=
4
−27
Find value of k.
2x
2
+kx−5=0 & x
2
−3x−4=0
→x
2
−3x−4=0
x
2
−4x+x−4=0
x(x−4)+1(x−4)=0
(x+1)(x−4)=0
x=−1 and x=4
→ one root is common
∴2(−1)
2
+k(−1)−5=0
∴2−k−5=0
∴k=−3
Or
2(4)
2
+k(4)−5=0
∴32+4k−5=0
∴k=
4
−27
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