Question

in fig if AB=CD , CD=EF and
x:y=3:2 , find z ​

Answer 1

Given: AB || CD, CD || EF, x:y=3:2

To Find: z

Solution:

Since, AB || CD and CD || EF we can say,

AB || EF

Now, Lets assume x = 3a and y = 2a

Now x = z (Alternate interior angles [AB || CD]) (i)

and, x + y = 180° (Co - interior angles [AB || EF])

=> 3a + 2a = 180°

=> 5a = 180°

=> a = 180/5 = 36°

Therefore, x = 108° , y = 72°

From eq (i) we conclude, z = 108°

(Assuming that first line was AB second was CD third was EF and transversal intersecting them)