Question

In fig if AB//CD,CD//EF and y:z =3:7, find the value of x

Answer 1

Answer:

In the given figure,AB∥CD,CD\parallel EFandy:z=3:7$$

Let y=3a and z=7a

∠DHI=y(vertically opposite angles)

∠DHI+∠FIH=180∘ (Interior angles on the same side of the transversal) 

⇒y+z=180∘

⇒3a+7a=180∘

⇒10a=180∘ or a=18∘

∴y=3×18∘=54∘ and z=7×18∘=126∘

Also,x+y=180∘

⇒x+54∘=180∘

∴x=180∘−54∘=126∘

Hence,x=126∘

Step-by-step explanation:

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