In fig., if AB||DE, angle BAC = 35degrees and angleCDE = 53degrees ,find angle DCE.
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3
35+53=88
88+DCE=180
DCE=92
88+DCE=180
DCE=92
Answered by
6
aed=35 (alt. angles)
cde=53
dce=180-(35+53)
=180-88
=92
cde=53
dce=180-(35+53)
=180-88
=92
Anonymous:
thanks shreya
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