Question

in fig if AB ll CD then find x

Answer 1

From the figure we have, ∠EPB=180 °−

(5x−20 ° )...(1)[ Since ∠BPE+∠QPB=180 ° ]

Again ∠PQD=∠QPB [ Similar angles]

or, 180 o −(5x−20 o )=2x−10 °

or, 7x=210 °

$or, x \frac{210}{7} =30$

30°