Question

in fig., if DP and DQ are respectively the bisector of angle CDA and angle CDB , then find angle PDQ​

Answer 1

Answer:

∠PDQ = 90

Step-by-step explanation:

Given : PD is bisector of ∠ADC and DQ bisector of ∠CDB , AB is straight line

∴ ∠PDC = ∠ADC/2           -----(i)

∠CDQ = ∠CDB/2                ------(ii)

add eq. (i) and (ii)

∠PDC + ∠CDQ =  ∠ADC/2 + ∠CDB/2

∠PDQ = ∠ADB / 2

∠PDQ = 180/2 = 90            ( ∠ADB is straight line)

Answer 2

Answer:

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Step-by-step explanation: