in fig., if DP and DQ are respectively the bisector of angle CDA and angle CDB , then find angle PDQ
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Answered by
18
Answer:
∠PDQ = 90
Step-by-step explanation:
Given : PD is bisector of ∠ADC and DQ bisector of ∠CDB , AB is straight line
∴ ∠PDC = ∠ADC/2 -----(i)
∠CDQ = ∠CDB/2 ------(ii)
add eq. (i) and (ii)
∠PDC + ∠CDQ = ∠ADC/2 + ∠CDB/2
∠PDQ = ∠ADB / 2
∠PDQ = 180/2 = 90 ( ∠ADB is straight line)
Answered by
0
Answer:
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Step-by-step explanation:
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