Question

In Fig., if lines PQ and RS intersect at point T,
such that PRT = 48°, RPT = 93° and
TSQ = 75°, find SQT.

Answer 1

Answer: here is ur answer

Step-by-step explanation:

In PRT,

By angle sum property of triangle

∠PRT+∠RPT+∠PTR=180°

 48°+93+<PTR=180°

 141°+<PTR=180°

 <PTR=180°-141°=39°

Also,

∠STQ=∠PTR

∠STQ=39°[because it’s V.O.A] vertically opposite angles

In ΔSQT

By angle sum property of triangle

∠SQT+∠STQ+∠TSQ=180°

<SQT+<39°+75°=180°

<SQT+114°=180°

<SQT=180°-114°=66°

hope it helps you