In fig:
If QT perpendicular to PR, angle TQR=40° and angle SPR =30° find x, y.
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Step-by-step explanation:
Let the point in which PS AND QT INTERSECT BE O
as QT perpendicular to PR
∠QTP = 90
and we know that ∠SPR = 30
ThEREFORE ∠TOP = 180 -120 = 60(ALL THREE ANGLES IN A TRIANGLE MAKE 180)
as it is vertically opposite to QOS
∠QOS = 60
THEREFORE ∠y = 180 - 100 = 80
now as ∠y = 80 ;
∠rsp = 100
therefore ∠x = 180 - 130 = 50
therefore ∠x = 50 ∠y = 80
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