Question

IN FIG. (II)SIDE BC OF TRIANGLE ABC IS PRODUCED TO D. IF ANGLE ACD = 128° AND ANGLE ABC =43° , FIND ANGLE BAC AND ANGLE ACB

Answer 1

In ABC,where it produce D, such that ACD=128° and angle ABC=43°. Angle BAC=180-ACD(striaght angle) therefore ANGLE ACB=180-128,ACB=52........(1)(PROVED). Then we will find angle ACB.Therefore , In ABC, angles ABC=43°(given), ACB=52°(proved above), BAC=180-(43°+52°),BAC=180-95,BAC=85.....(2).
THEREFORE (ACB=52 and BAC=85).
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Answer 2

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