Question

In fig. (it) angle A = angle D = 90°, angle C = 52º. BE is the bisector of angle B. AD and BE intersects at O. Find (a) angle BOD (b) angle AEO Hence deduce that AE = AB​

Answer 1

Step-by-step explanation:

angle A+ angle B+ angle C=180°( angle sum property)

90°+ angle B + 52°= 180°

angle B = 180°-142°

angle B =38°

angle DBO =1/2 angle DBA ( DBO = OBA)

angle DBO =1/2*38°

angle DBO =19°

in ∆ DBO

angle DBO + angle BOD + angle ODB = 180°(angle sum property)

19°+ angle BOD + 90°= 180°

angle BOD=180°-109°

angle BOD=71°

that's all I know. Please ask others for the next answer. If I find it out I will certainly update it

hope it helps ☺️

I found it out

In ∆ABE angle A + angle E + angle B=180°(angle sum property)

90° + angle E + 19°=180°( angle DBO= angle OBA)

angle E =180°-109°

angle E =71°

hence, AB is not likely to be equal to AE

but AE =AO

as angle DOB =angle EOA (V.O.A)

so ∆AOE is isosceles