In Fig., it is given that AB = BC and AD = EC. Prove that
(i)
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Given:-
- AB = BC,
- AD = EC
TO Proof:-
- ∆ABE ≅ ∆CBD
- BD = BE
Proof:-
(i) In ∆ABC,
∵ AB = BC | Given
∴ ∠BAC = ∠BCA ____(1)
| Angles opposite to equal sides of a triangle are equal |
AD = EC | Given
⇒ AD + DE = EC + DE
⇒ AE = CD ___..(2)
Now, in ∆ABE and ∆CBD,
AE = CD | From (2)
AB = CB | Given
∠BAE = ∠BCD | From (1)
∴ ∆ABE ≅ ∆CBD | SAS congruence rule.
(ii) BD = BE ( by CPCT)
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